Q.If \(a : b = 3 : 4\) and \(x : y = 5 : 7\), then find the value of \((3ax - by) : (4by - 7ax)\).

\(a : b = 3 : 4\) ⇒ \(\frac{a}{b} = \frac{3}{4}\) ⇒ \(a = \frac{3b}{4}\) Again, \(x : y = 5 : 7\) ⇒ \(\frac{x}{y} = \frac{5}{7}\) ⇒ \(x = \frac{5y}{7}\) ∴ \((3ax - by) : (4by - 7ax)\) \(= (3 × \frac{3b}{4} × \frac{5y}{7} - by) : (4by - 7 × \frac{3b}{4} × \frac{5y}{7})\) \(= (\frac{45by}{28} - by) : (4by - \frac{105by}{28})\) \(= (\frac{45}{28} - 1) : (4 - \frac{105}{28})\) \(= \frac{17}{28} : \frac{7}{28}\) \(= 17 : 7\)
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