The current value of the machine \((p) = ₹180,000\) Rate of depreciation \((r) = 10\%\) Time \((n) = 3\) years ∴ After 3 years, the value of the machine will be: \[ = p\left(1 - \frac{r}{100}\right)^n = 180000\left(1 - \frac{10}{100}\right)^3 = 180000\left(\frac{90}{100}\right)^3 = 180000 \times \left(\frac{9}{10}\right)^3 = 180000 \times \frac{9}{10} \times \frac{9}{10} \times \frac{9}{10} = ₹131,220 \] ∴ The value of the machine after 3 years will be ₹131,220.