Q.If \( \cfrac{1}{y} - \cfrac{1}{x} \propto \cfrac{1}{x - y} \), prove that \( x \propto y \).


\[ \cfrac{1}{y}-\cfrac{1}{x}\propto \cfrac{1}{x-y} \] \[ \text{or, } \cfrac{x-y}{xy}= \cfrac{k}{x-y} \quad [k \text{ is a nonzero constant}] \] \[ \text{or, } \cfrac{(x-y)^2}{xy}=k \] \[ \text{or, } \cfrac{x^2+y^2-2xy}{xy}=k \] \[ \text{or, } \cfrac{x^2+y^2}{xy}-2=k \] \[ \text{or, } \cfrac{x^2+y^2}{xy}=k+2 \] \[ \text{or, } \cfrac{x^2+y^2}{2xy}=\cfrac{k+2}{2}=m \] \[ \text{Let, } \cfrac{k+2}{2}=m \] \[ \text{or, } \cfrac{x^2+y^2+2xy}{x^2+y^2-2xy}=\cfrac{m+1}{m-1} \] \[ \text{Using addition and division method} \] \[ \text{or, } \cfrac{(x+y)^2}{(x-y)^2}=n \] \[ \text{Let, } \cfrac{m+1}{m-1}=n \] \[ \text{or, } \cfrac{(x+y)}{(x-y)}=\sqrt{n} \] \[ \text{or, } \cfrac{(x+y+x-y)}{(x+y-x+y)}=\cfrac{\sqrt{n}+1}{\sqrt{n}-1} \] \[ \text{Using addition and division method} \] \[ \text{or, } \cfrac{\cancel2x}{\cancel2y}=\cfrac{\sqrt{n}+1}{\sqrt{n}-1}=\text{ constant} \] \[ \therefore x\propto y \quad (\text{Proved}) \]
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