Answer: C
Let the center of the circle be O. \(\therefore\) The central angle \(\angle\)AOB = 2 × \(\angle\)APB = 2 × 35° = 70° Also, OA and OB are radii drawn to the points of tangency of the tangents. \(\therefore\) \(\angle\)OAC = \(\angle\)OBC = 90° \(\therefore\) \(\angle\)ACB = 180° − (\(\angle\)AOB + \(\angle\)OAC + \(\angle\)OBC) = 360° − (70° + 90° + 90°) = 360° − 250° = 110°
Let the center of the circle be O. \(\therefore\) The central angle \(\angle\)AOB = 2 × \(\angle\)APB = 2 × 35° = 70° Also, OA and OB are radii drawn to the points of tangency of the tangents. \(\therefore\) \(\angle\)OAC = \(\angle\)OBC = 90° \(\therefore\) \(\angle\)ACB = 180° − (\(\angle\)AOB + \(\angle\)OAC + \(\angle\)OBC) = 360° − (70° + 90° + 90°) = 360° − 250° = 110°