Q.If \(\theta\) is a positive acute angle and \(\sin \theta = \frac{\sqrt{3}}{2}\), then what is the value of \(\tan(\theta - 15^\circ)\)?

\(\sin \theta = \frac{\sqrt{3}}{2}\) That is, \(\sin \theta = \sin 60^\circ\) So, \(\theta = 60^\circ\) Therefore, \[ \tan(\theta - 15^\circ) = \tan(60^\circ - 15^\circ) = \tan 45^\circ = 1 \](Answer )
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