Q.Prove that all angles subtended by the same arc at the circumference of a circle are equal.

**Given:** Let ∠ACB and ∠ADB be any two angles subtended by the arc AB of a circle with center O. **To Prove:** All angles subtended by the arc AB at the circumference (i.e., ∠ACB and ∠ADB) are equal. **Construction:** Join points O and A, and O and B with straight lines. **Proof:** ∠AOB is the central angle formed by the arc AB, and ∠ACB and ∠ADB are angles at the circumference.  ∴ ∠AOB = 2∠ACB  and ∠AOB = 2∠ADB Therefore, 2∠ACB = 2∠ADB  ∴ ∠ACB = ∠ADB  [Proved]
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