Q.In the circle with center \( O \), if \( AOB \) is a diameter and point \( C \) is on the circle such that \( AC = 3 \) cm and \( BC = 4 \) cm, what is the length of \( AB \)? (a) 3 cm (b) 4 cm (c) 5 cm (d) 8 cm
Answer: C

Since \( \angle ACB = 90^\circ \) (right angle, as it's an angle in a semicircle), In the right-angled triangle \( \Delta ABC \),

\( AB^2 = AC^2 + BC^2 = 3^2 + 4^2 \)
\(= 9 + 16 = 25 \)
Thus, \( AB = 5 \, \text{cm} \)

So, the length of \( AB \) is 5 cm.
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