Answer: C
Since \( \angle ACB = 90^\circ \) (right angle, as it's an angle in a semicircle), In the right-angled triangle \( \Delta ABC \),
\( AB^2 = AC^2 + BC^2 = 3^2 + 4^2 \)
\(= 9 + 16 = 25 \)
Thus, \( AB = 5 \, \text{cm} \)
So, the length of \( AB \) is 5 cm.
Since \( \angle ACB = 90^\circ \) (right angle, as it's an angle in a semicircle), In the right-angled triangle \( \Delta ABC \),
\( AB^2 = AC^2 + BC^2 = 3^2 + 4^2 \)
\(= 9 + 16 = 25 \)
Thus, \( AB = 5 \, \text{cm} \)
So, the length of \( AB \) is 5 cm.