Answer: B
Total number of terms \(n = 10\) ∴ Median = \(\frac{1}{2}\) × (5th term + 6th term) \[ = \frac{1}{2}(x + y + 2) = \frac{x + y + 2}{2} \] According to the condition: \[ \frac{x + y + 2}{2} = 64 \Rightarrow x + y + 2 = 128 \Rightarrow x + y = 128 - 2 \Rightarrow x + y = 126 \]
Total number of terms \(n = 10\) ∴ Median = \(\frac{1}{2}\) × (5th term + 6th term) \[ = \frac{1}{2}(x + y + 2) = \frac{x + y + 2}{2} \] According to the condition: \[ \frac{x + y + 2}{2} = 64 \Rightarrow x + y + 2 = 128 \Rightarrow x + y = 128 - 2 \Rightarrow x + y = 126 \]