If \( \sin(\theta - 30^\circ) = \frac{1}{2} \), then \( \cos \theta = \frac{1}{2} \)
Since \( \sin(\theta - 30^\circ) = \sin 30^\circ \), Then, \( \theta - 30^\circ = 30^\circ \) So, \( \theta = 30^\circ + 30^\circ = 60^\circ \) \(\therefore \cos \theta = \cos 60^\circ = \frac{1}{2} \)