Q.On triangle \( \triangle ABC \), points P and Q are such that \( \angle ABC = \angle APQ \). Given that \( AP = 3.6 \) cm, \( QC = 1.6 \) cm, and \( AQ = 4.8 \) cm, find the length of \( PB \). (a) 1.2 cm (b) 2.4 cm (c) 6 cm (d) None of the above
Answer: A
Here, \( \angle ABC = \angle APQ \) ∴ PQ is parallel to BC ∴ \( \frac{AP}{PB} = \frac{AQ}{QC} \) i.e., \( \frac{3.6}{PB} = \frac{4.8}{1.6} \) ⇒ \( PB = \frac{3.6 \times 1.6}{4.8} = 1.2 \) ∴ PB = 1.2 cm.
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