Answer: A
Here, \( \angle ABC = \angle APQ \) ∴ PQ is parallel to BC ∴ \( \frac{AP}{PB} = \frac{AQ}{QC} \) i.e., \( \frac{3.6}{PB} = \frac{4.8}{1.6} \) ⇒ \( PB = \frac{3.6 \times 1.6}{4.8} = 1.2 \) ∴ PB = 1.2 cm.
Here, \( \angle ABC = \angle APQ \) ∴ PQ is parallel to BC ∴ \( \frac{AP}{PB} = \frac{AQ}{QC} \) i.e., \( \frac{3.6}{PB} = \frac{4.8}{1.6} \) ⇒ \( PB = \frac{3.6 \times 1.6}{4.8} = 1.2 \) ∴ PB = 1.2 cm.