Answer: D
Since \(\triangle\)ABC and \(\triangle\)POR are similar triangles, \(\therefore \frac{PE}{AD} = \frac{QR}{BC}\) So, \(PE = \frac{QR \times AD}{BC} = \frac{4 \times 3}{5} = \frac{12}{5} = 2.4\) \(\therefore\) The height PE is 2.4 cm.
Since \(\triangle\)ABC and \(\triangle\)POR are similar triangles, \(\therefore \frac{PE}{AD} = \frac{QR}{BC}\) So, \(PE = \frac{QR \times AD}{BC} = \frac{4 \times 3}{5} = \frac{12}{5} = 2.4\) \(\therefore\) The height PE is 2.4 cm.