Let the diameter of the solid sphere be \(2r\) units. ∴ The height of the right circular cylinder and the right circular cone is also \(2r\) units, and the radius of the base is \(r\) units. ∴ The ratio of the volumes of the solid right circular cylinder, the solid right circular cone, and the solid sphere is: \[ = \pi r^2 \cdot 2r : \frac{1}{3} \pi r^2 \cdot 2r : \frac{4}{3} \pi r^3 \] \[ = 2\pi r^3 : \frac{2}{3}\pi r^3 : \frac{4}{3}\pi r^3 \] \[ = 1 : \frac{1}{3} : \frac{2}{3} \] \[ = 3 : 1 : 2 \]