Q.If the length of the diagonal of each face of a cube is \(6\sqrt{2}\) cm, what is the total surface area of the cube?
Diagonal of each face of the cube = \(\sqrt{2} \times\) side
∴ \(\sqrt{2} \times\) side = \(6\sqrt{2}\)
⇒ side = 6 cm
Total surface area of the cube = \(6 \times\) (side)\(^2\)
= \(6 \times 6^2\) sq. cm = \(6 \times 36\) sq. cm
= 216 sq. cm (Answer)