Q.If the length of the diagonal of each face of a cube is \(6\sqrt{2}\) cm, what is the total surface area of the cube?

Diagonal of each face of the cube = \(\sqrt{2} \times\) side ∴ \(\sqrt{2} \times\) side = \(6\sqrt{2}\) ⇒ side = 6 cm Total surface area of the cube = \(6 \times\) (side)\(^2\) = \(6 \times 6^2\) sq. cm = \(6 \times 36\) sq. cm = 216 sq. cm (Answer)
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