Q.If \(0^\circ \leq \alpha < 90^\circ\), find the minimum value of \((\sec^2α + \cos^2α)\). (a) 1 (b) 2 (c) \(\cfrac{5}{2}\) (d) 0
Answer: B
\(sec^2α + \cos^2α\)

\(= (secα - cosα)^2 + 2secα \cdot cosα\)

\(= (secα - cosα)^2 + 2\)

\(≥ 2\) [∵ the square of any quantity cannot be negative]

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