Given: \[ \cos^4\theta - \sin^4\theta = \cfrac{2}{3} \] Then, \[ (\cos^2\theta)^2 - (\sin^2\theta)^2 = \cfrac{2}{3} \Rightarrow (\cos^2\theta + \sin^2\theta)(\cos^2\theta - \sin^2\theta) = \cfrac{2}{3} \Rightarrow (\cos^2\theta - \sin^2\theta) = \cfrac{2}{3} \quad [\text{Since } \cos^2\theta + \sin^2\theta = 1] \] Now, \[ 1 - \sin^2\theta - \sin^2\theta = \cfrac{2}{3} \Rightarrow 1 - 2\sin^2\theta = \cfrac{2}{3} \quad \text{[Answer]} \]