Q.If \(\sin^2\theta + \sin^4\theta = 1\), then prove that \(\tan^4\theta - \tan^2\theta = 1\).

\( \sin^4\theta + \sin^2\theta = 1 \)
Or, \( \sin^4\theta = 1 - \sin^2\theta \)
Or, \( \sin^4\theta = \cos^2\theta \)
Or, \( \cfrac{\sin^4\theta}{\cos^4\theta} = \cfrac{\cos^2\theta}{\cos^4\theta} \)

[Dividing both sides by \( \cos^4\theta \)]

Or, \( \tan^4\theta = \cfrac{1}{\cos^2\theta} = \sec^2\theta \)

Now, \( \tan^4\theta - \tan^2\theta \)
\( = \sec^2\theta - \tan^2\theta \) [Since \( \tan^4\theta = \sec^2\theta \)]
\( = 1 \) (Proved) [Since \( \sec^2\theta - \tan^2\theta = 1 \)]
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