Q.If the radius of a sphere is decreased by 10%, by what percentage will the volume decrease? (a) 10% (b) 25% (c) 27.1% (d) 29.7%
Answer: C
Let the original radius be \(r\) units \(\therefore\) New radius = \(\cfrac{9r}{10}\) units \(\therefore\) Percentage decrease in volume \(= \cfrac{\cfrac{4}{3}\pi r^3 - \cfrac{4}{3}\pi (\cfrac{9r}{10})^3}{\cfrac{4}{3}\pi r^3} \times 100\%\) \(= \left(1 - \cfrac{729}{1000}\right) \times 100\%\) \(= \cfrac{271}{10}\%\) \(= 27.1\%\)
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