Q.The radius of the circumcircle of an equilateral triangle with side length \(5\sqrt{3}\) cm will be — (a) 6 cm (b) 5 cm (c) 4 cm (d) 3 cm
Answer: B
The height of the equilateral triangle is: \(\frac{\sqrt{3}}{2} \times 5\sqrt{3}\) cm \(= \frac{15}{2}\) cm \(\therefore\) The radius of the circumcircle = \(\frac{15}{2} \times \frac{2}{3}\) cm \(= 5\) cm.
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