Answer: B
The height of the equilateral triangle is: \(\frac{\sqrt{3}}{2} \times 5\sqrt{3}\) cm \(= \frac{15}{2}\) cm \(\therefore\) The radius of the circumcircle = \(\frac{15}{2} \times \frac{2}{3}\) cm \(= 5\) cm.
The height of the equilateral triangle is: \(\frac{\sqrt{3}}{2} \times 5\sqrt{3}\) cm \(= \frac{15}{2}\) cm \(\therefore\) The radius of the circumcircle = \(\frac{15}{2} \times \frac{2}{3}\) cm \(= 5\) cm.