Let the radius of the base of the right circular cone and the hemisphere be \(r\), and their heights be \(h_1\) and \(h_2\) respectively. For the hemisphere, the radius \(r = h_2\)
\(\therefore\) According to the question, \(\cfrac{1}{3} \pi r^2 h_1 = \cfrac{2}{3} \pi r^3\) Or, \(h_1 = 2r\) Or, \(h_1 = 2h_2\) [since \(r = h_2\)] Or, \(\cfrac{h_1}{h_2} = 2\) \(\therefore h_1 : h_2 = 2 : 1\)
\(\therefore\) The ratio of the heights of the right circular cone and the hemisphere is \(2 : 1\).