Q.A right circular cone and a hemisphere have equal base areas and volumes. Determine the ratio of their heights.

Let the radius of the base of the right circular cone and the hemisphere be \(r\), and their heights be \(h_1\) and \(h_2\) respectively. For the hemisphere, the radius \(r = h_2\)

\(\therefore\) According to the question, \(\cfrac{1}{3} \pi r^2 h_1 = \cfrac{2}{3} \pi r^3\) Or, \(h_1 = 2r\) Or, \(h_1 = 2h_2\) [since \(r = h_2\)] Or, \(\cfrac{h_1}{h_2} = 2\) \(\therefore h_1 : h_2 = 2 : 1\)

\(\therefore\) The ratio of the heights of the right circular cone and the hemisphere is \(2 : 1\).
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