In the figure, a straight line intersects two concentric circles centered at point O, at points A and B on one circle, and at points C and D on the other. We have to prove that AC = BD. Construction: Draw a perpendicular OP from the center O to chord AB. Proof: Since a perpendicular drawn from the center of a circle to a chord bisects the chord, point P is the midpoint of AB. ∴ CP = PD and AP = PB ∵ AP = PB So, AC + CP = PD + BD Therefore, AC = BD [∵ CP = PD] (Proved)