Q.In a circle with center \(O\), \(\bar{AB}\) is a diameter. On the opposite side of the circumference from the diameter \(\bar{AB}\), there are two points \(C\) and \(D\) such that \(\angle AOC = 130°\) and \(\angle BDC = x°\). Find the value of \(x\). (a) 25° (b) 50° (c) 60° (d) 65°
Answer: A
\(\angle\)COB = \(180° - 130° = 50°\)
The central angle subtended by arc \(CB\) is \(\angle\)COB, and the inscribed angle subtended by the same arc is \(\angle\)CDB.
∴ \(\angle\)CDB = \(\cfrac{1}{2}\) \(\angle\)COB = \(\cfrac{1}{2}\) × \(50° = 25°\).
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