Q.At an annual simple interest rate of \(x\%\), if the interest on a principal in \(x\) years is \(x\) rupees, then the amount of the principal is – (a) \(x\) rupees (b) \(100x\) rupees (c) \(\cfrac{100}{x}\) rupees (d) \(\cfrac{100}{x^2}\) rupees
Answer: C
\(n = x\) years, \(r = x\%\), \(I = x\) rupees.
\(\therefore p = \cfrac{100x}{x \times x}\) rupees = \(\cfrac{100}{x}\) rupees.
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