Q.If a cuboid has \(x\) number of vertices, \(y\) number of edges, and \(z\) number of faces, then what is the value of \((x - y + z)^2\)? (a) 2 (b) 4 (c) 6 (d) None of the above
Answer: B
In this case, \(x = 8, y = 12, z = 6\)
\((x - y + z)^2\)
\(= (8 - 12 + 6)^2\)
\(= (2)^2\)
\(= 4\)