Answer: C
Time \((t) = \cfrac{1}{365}\) years
Interest rate \((r) = 10\%\)
Total interest amount \((I) = ₹1\)
\(\therefore\) Principal amount \((p) = \cfrac{100 \times I}{t \times r}\)
\(= \cfrac{100 \times 1}{\cfrac{1}{365} \times 10}\)
\(= 3650\) rupees.
Time \((t) = \cfrac{1}{365}\) years
Interest rate \((r) = 10\%\)
Total interest amount \((I) = ₹1\)
\(\therefore\) Principal amount \((p) = \cfrac{100 \times I}{t \times r}\)
\(= \cfrac{100 \times 1}{\cfrac{1}{365} \times 10}\)
\(= 3650\) rupees.