Let the side length of the cube = radius of the sphere = \(a\) units. \(\therefore\) Volume of the cube = \(r^3\) cubic units. And volume of the sphere = \(\frac{4}{3} \pi r^3\) cubic units = \(\frac{4 \times 22}{3 \times 7} r^3\) cubic cm = \(\frac{88}{21} r^3\) cubic cm > \(r^3\) cubic cm > Volume of the cube \(\therefore\) The volume of the sphere will be greater than that of the cube.