Q.If ABCD is a cyclic quadrilateral inscribed in a circle with center O, then prove that AB + CD = AD + BC.

ABCD is a quadrilateral inscribed in a circle with center O. Let AB, BC, CD, and DA touch the circle at points P, Q, R, and S respectively. To prove: AB + CD = AD + BC Proof: From the external point A, AP and AS are tangents to the circle. ⇒ AP = AS Similarly, - BP = BQ - CQ = CR - DR = DS So, \[ AB + CD = AP + BP + CR + DR = AS + BQ + CQ + DS = (AS + DS) + (BQ + CQ) = AD + BC \] proved: AB + CD = AD + BC
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