Answer: D
Let the angle of elevation of the sun be \(\theta\). \(\therefore\) Length of the shadow = \(\cfrac{1}{\sqrt{3}} \times\) height of the pole Or, shadow length / pole height = \(\cfrac{1}{\sqrt{3}}\) That is, base / perpendicular = \(\cfrac{1}{\sqrt{3}}\) So, \(\cot \theta = \cfrac{1}{\sqrt{3}} = \cot 60^\circ\) Therefore, \(\theta = 60^\circ\)
Let the angle of elevation of the sun be \(\theta\). \(\therefore\) Length of the shadow = \(\cfrac{1}{\sqrt{3}} \times\) height of the pole Or, shadow length / pole height = \(\cfrac{1}{\sqrt{3}}\) That is, base / perpendicular = \(\cfrac{1}{\sqrt{3}}\) So, \(\cot \theta = \cfrac{1}{\sqrt{3}} = \cot 60^\circ\) Therefore, \(\theta = 60^\circ\)