Q.A circle has center ‘O’, and a point P lies 26 cm away from it. If the length of the tangent drawn from point P to the circle is 10 cm, then what is the radius of the circle?

Assume PT is the tangent drawn from point P. Given: PT = 10 cm, OP = 26 cm In the right-angled triangle \(\triangle PTO\), \[ OT^2 = OP^2 - PT^2 \] \[ \Rightarrow OT^2 = 26^2 - 10^2 = 676 - 100 = 576 \] \[ \Rightarrow OT = \sqrt{576} = 24 \] \[ \therefore \text{The radius of the circle (OT)} = 24 \, \text{cm} \]
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