Q.Two tangents are drawn to a circle from points A and B on the circumference, and they intersect at point C. Another point P lies on the circumference, on the side opposite to where point C is located with respect to the center. If \(\angle\)APB = 35°, then what is the measure of \(\angle\)ACB? (a) 145° (b) 55° (c) 110° (d) None of the above
Answer: C
Let the center of the circle be O. \(\therefore\) The central angle \(\angle\)AOB = 2 × \(\angle\)APB = 2 × 35° = 70° Also, OA and OB are radii drawn to the points of tangency of the tangents. \(\therefore\) \(\angle\)OAC = \(\angle\)OBC = 90° \(\therefore\) \(\angle\)ACB = 180° − (\(\angle\)AOB + \(\angle\)OAC + \(\angle\)OBC) = 360° − (70° + 90° + 90°) = 360° − 250° = 110°
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