Q.In triangle ∆ABC, a straight line parallel to side BC intersects sides AB and AC at points X and Y respectively. If AX = 2.4 cm, AY = 3.2 cm, and YC = 4.8 cm, find the length of AB.

In triangle ∆ABC, XY ∥ BC and AC = AY + YC = 3.2 + 4.8 = 8 cm Because XY ∥ BC in ∆ABC, ∴ \( \frac{AX}{AB} = \frac{AY}{AC} \) i.e., \( \frac{2.4}{AB} = \frac{3.2}{8} \) i.e., \( AB = \frac{2.4 \times 8}{3.2} \) i.e., \( AB = 6 \) ∴ AB = 6 cm
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