Let AB = 10 cm, so AP = 5 cm OA = 13 cm Therefore, in the right-angled triangle \(\triangle OAP\): \[ OP^2 = OA^2 - AP^2 \] \[ \Rightarrow OP^2 = 13^2 - 5^2 = 169 - 25 = 144 \] \[ \Rightarrow OP = \sqrt{144} = 12 \] Hence, the distance from the center of the circle to the chord is 12 cm.