Q.If a circle is centered at point 'O' with a radius of 13 cm and chord AB has a length of 10 cm, what is the distance from point 'O' to chord AB?

Let AB = 10 cm, so AP = 5 cm OA = 13 cm Therefore, in the right-angled triangle \(\triangle OAP\): \[ OP^2 = OA^2 - AP^2 \] \[ \Rightarrow OP^2 = 13^2 - 5^2 = 169 - 25 = 144 \] \[ \Rightarrow OP = \sqrt{144} = 12 \] Hence, the distance from the center of the circle to the chord is 12 cm.
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