Let \[ \cfrac{x}{2} = \cfrac{y}{3} = \cfrac{z}{4} = k \] \[ \therefore x = 2k,\quad y = 3k,\quad z = 4k \] Now, \[ \cfrac{3x + 4y + 8z}{x + 3y} = \cfrac{3 \cdot 2k + 4 \cdot 3k + 8 \cdot 4k}{2k + 3 \cdot 3k} = \cfrac{6k + 12k + 32k}{2k + 9k} = \cfrac{50k}{11k} = \cfrac{50}{11} = 4\cfrac{6}{11} \quad \text{[Answer]} \]