Answer: B
Principal \((p) = 350\) rupees
Time \((t) = 1\frac{1}{3} = \cfrac{4}{3}\) years
Interest rate \((r) = 2 × 12\% = 24\%\)
\(\therefore\) Total interest amount \((I) = \cfrac{ptr}{100}\)
\(= \cfrac{350 × \cfrac{4}{3} × 24}{100}\)
\(= \cfrac{\cancel{350}14 × \cfrac{\cancel4}{\cancel3} × \cancel{24}8}{\cancel{100}\cancel4}\)
\(= 112\) rupees.
Principal \((p) = 350\) rupees
Time \((t) = 1\frac{1}{3} = \cfrac{4}{3}\) years
Interest rate \((r) = 2 × 12\% = 24\%\)
\(\therefore\) Total interest amount \((I) = \cfrac{ptr}{100}\)
\(= \cfrac{350 × \cfrac{4}{3} × 24}{100}\)
\(= \cfrac{\cancel{350}14 × \cfrac{\cancel4}{\cancel3} × \cancel{24}8}{\cancel{100}\cancel4}\)
\(= 112\) rupees.