The radius of the conical part = radius of the hemispherical part \(r = 2.5\) cm Height of the cone \(h = 9\) cm Volume of the ice cream = Volume of the conical part + Volume of the hemispherical part \[ = \frac{1}{3}\pi r^2h + \frac{2}{3}\pi r^3 \quad \text{cubic cm} \] Substituting the values: \[ = \frac{1}{3} \times \frac{22}{7} \times (2.5)^2 \times 9 + \frac{2}{3} \times \frac{22}{7} \times (2.5)^3 \] Factorizing: \[ = \frac{22}{7} \times (2.5)^2 \left[3 + \frac{2}{3} \times 2.5\right] = \frac{22}{7} \times 6.25 \left[3 + \frac{5}{3}\right] = \frac{22}{7} \times 6.25 \times \frac{14}{3} = \frac{275}{3} = 91 \frac{2}{3} \text{ cubic cm} \]