Let the depth of the pit be \(d\) meters. ∴ Volume of soil dug from the pit = \(27 \times 18.2 \times d\) cubic meters Now, the low-lying land is to be raised by 6.5 decimeters = 0.65 meters ∴ According to the question: \[ 27 \times 18.2 \times d = 48 \times 31.5 \times 0.65 \Rightarrow d = \frac{48 \times 31.5 \times 0.65}{27 \times 18.2} \Rightarrow d = 2 \] ∴ The pit must be 2 meters deep