Answer: A
OA = OB = Radius of the circle \(\therefore \angle\)OAB = \(\angle\)OBA = \(\frac{180^\circ - 120^\circ}{2} = 30^\circ\) Again, OA is the radius drawn to the point of tangency \(\therefore \angle\)OAT = \(90^\circ\) \(\therefore \angle\)BAT = \(\angle\)OAT − \(\angle\)OAB = \(90^\circ − 30^\circ = 60^\circ\)
OA = OB = Radius of the circle \(\therefore \angle\)OAB = \(\angle\)OBA = \(\frac{180^\circ - 120^\circ}{2} = 30^\circ\) Again, OA is the radius drawn to the point of tangency \(\therefore \angle\)OAT = \(90^\circ\) \(\therefore \angle\)BAT = \(\angle\)OAT − \(\angle\)OAB = \(90^\circ − 30^\circ = 60^\circ\)