Q.AB is a chord of a circle centered at O, and PT is a tangent to the circle at point A. If ∠ AOB = 120°, then what is the measure of ∠ BAT? (a) 60° (b) 30° (c) 90° (d) 45°
Answer: A
OA = OB = Radius of the circle \(\therefore \angle\)OAB = \(\angle\)OBA = \(\frac{180^\circ - 120^\circ}{2} = 30^\circ\) Again, OA is the radius drawn to the point of tangency \(\therefore \angle\)OAT = \(90^\circ\) \(\therefore \angle\)BAT = \(\angle\)OAT − \(\angle\)OAB = \(90^\circ − 30^\circ = 60^\circ\)
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