Q.In triangle △ABC, if AB = \((2a - 1)\) cm, AC = \(2\sqrt{2a}\) cm, and BC = \((2a + 1)\) cm, then find the measure of ∠BAC.

AB² + AC² = (2a − 1)² + (2√2a)² = (2a − 1)² + 4 × 2a = (2a + 1)² = BC²

\(\therefore\) ∠ABC is a right-angled triangle, where ∠BAC is the right angle. \(\therefore\) ∠BAC = 90° (Answer)
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