Q.A man takes a loan of ₹500 at 6% simple interest per annum. Exactly two years after taking the first loan, he takes a second loan of ₹900 at 4% simple interest per annum. After how many years from the time of the first loan will the interest amounts on both loans be equal? Also, what will be the total interest on both loans at that time?

Let the interest amounts on both loans become equal after \(x\) years from the time the first loan was taken. Therefore, the interest on the first loan is: \[ \frac{500 \times x \times 6}{100} \text{ rupees} \] For the second loan, the time is \((x - 2)\) years. So, the interest on the second loan is: \[ \frac{900 \times (x - 2) \times 4}{100} \text{ rupees} \] According to the question: \[ \frac{500 \times x \times 6}{100} = \frac{900 \times (x - 2) \times 4}{100} \] Solving: \[ 30x = 36x - 72 \Rightarrow -6x = -72 \Rightarrow x = 12 \] Therefore, the interest amounts on both loans will be equal 12 years after the first loan was taken. At that time, the total interest on both loans will be: \[ \left\{ \frac{500 \times 12 \times 6}{100} + \frac{900 \times (12 - 2) \times 4}{100} \right\} = \left\{ 360 + 360 \right\} = 720 \text{ rupees} \]
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