\(3x^2 + 7x + 23 = (x + 4)(x + 3) + 2\) Or, \(3x^2 + 7x + 23 = x^2 + 3x + 4x + 12 + 2\) Or, \(3x^2 + 7x + 23 = x^2 + 7x + 14\) Or, \(3x^2 + 7x + 23 - x^2 - 7x - 14 = 0\) Or, \(2x^2 + 9 = 0\) After simplifying the equation, we see that there is no term containing \(x\). So, when written in the form of a quadratic equation \(ax^2 + bx + c = 0\) where \(a \ne 0\), it becomes: \(2x^2 + 0 \cdot x + 9 = 0\) [Here, \(a = 2 (\ne 0),\ b = 0,\ c = 9\)]