At an annual simple interest rate of \(r\%\), if the interest on a principal for \(n\) years is \(\frac{pnr}{25}\) rupees, then the principal amount will be \(4p\) rupees. Time \((t) = n\) years Rate of interest \((r) = r\%\) Interest \((I) = \frac{pnr}{25}\) rupees Therefore, Principal \((P) = \frac{100 \times I}{t \times r}\) \[ = \frac{100 \times \frac{pnr}{25}}{n \times r} = \frac{4pnr}{nr} = 4p \text{ rupees} \]