If \( \sin^2 \theta + 2x \cos^2 \theta = 1 \), then the value of \( x \) will be \(\frac{1}{2}\).
Given: \[ \sin^2 \theta + 2x \cos^2 \theta = 1 \] Using the identity: \[ \sin^2 \theta + \cos^2 \theta = 1 \Rightarrow 1 - \sin^2 \theta = \cos^2 \theta \] So, \[ 2x \cos^2 \theta = 1 - \sin^2 \theta = \cos^2 \theta \Rightarrow 2x \cos^2 \theta = \cos^2 \theta \Rightarrow 2x = 1 \Rightarrow x = \frac{1}{2} \]