\[
\angle POB = 180^\circ - 120^\circ = 60^\circ
\]
\[
\because \text{The central angle } \angle POB \text{ subtends arc PB, and the inscribed angle } \angle PQB = x^\circ
\]
\[
\therefore x^\circ = \cfrac{1}{2} \times \angle POB = \cfrac{1}{2} \times 60^\circ = 30^\circ
\]
\[
\therefore x = 30
\]