Q.In triangle \( \triangle ABC \), if \( \angle ABC = 90^\circ \), \( AB = 6 \) cm, and \( BC = 8 \) cm, then what is the length of the circumradius of triangle \( \triangle ABC \)?

In a right-angled triangle \( \triangle ABC \): AC² = AB² + BC² ⇒ AC² = 6² + 8² = 36 + 64 = 100 ⇒ AC = √100 = 10 In a right-angled triangle, the circumradius is half the length of the hypotenuse. \(\therefore\) The circumradius of \( \triangle ABC \) = \( \frac{10}{2} \) cm = 5 cm.
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