In a right-angled triangle \( \triangle ABC \): AC² = AB² + BC² ⇒ AC² = 6² + 8² = 36 + 64 = 100 ⇒ AC = √100 = 10 In a right-angled triangle, the circumradius is half the length of the hypotenuse. \(\therefore\) The circumradius of \( \triangle ABC \) = \( \frac{10}{2} \) cm = 5 cm.