Answer: D
Given: \(2\sin 2\theta - \sqrt{3} = 0\) i.e., \(2\sin 2\theta = \sqrt{3}\) i.e., \(\sin 2\theta = \frac{\sqrt{3}}{2} = \sin 60^\circ\) i.e., \(2\theta = 60^\circ\) i.e., \(\theta = 30^\circ\) \(\therefore \csc \theta = \csc 30^\circ = 2\)
Given: \(2\sin 2\theta - \sqrt{3} = 0\) i.e., \(2\sin 2\theta = \sqrt{3}\) i.e., \(\sin 2\theta = \frac{\sqrt{3}}{2} = \sin 60^\circ\) i.e., \(2\theta = 60^\circ\) i.e., \(\theta = 30^\circ\) \(\therefore \csc \theta = \csc 30^\circ = 2\)