Answer: A
A cyclic trapezium is an isosceles trapezium.
∴ \(\angle\)PSR = \(\angle\)QRS = 110°
Also, \(\angle\)PSQ = 90° [Angle in a semicircle]
∴ \(\angle\)QSR = \(\angle\)PSR - \(\angle\)PSQ = 110° - 90° = 20°.
A cyclic trapezium is an isosceles trapezium.
∴ \(\angle\)PSR = \(\angle\)QRS = 110°
Also, \(\angle\)PSQ = 90° [Angle in a semicircle]
∴ \(\angle\)QSR = \(\angle\)PSR - \(\angle\)PSQ = 110° - 90° = 20°.