Q.PQRS is a cyclic trapezium. PQ is a diameter of the circle, and PO || SR. If \(\angle\)QRS = 110°, then the value of \(\angle\)QSR is - (a) 20° (b) 25° (c) 30° (d) 40°
Answer: A
A cyclic trapezium is an isosceles trapezium.
∴ \(\angle\)PSR = \(\angle\)QRS = 110°
Also, \(\angle\)PSQ = 90° [Angle in a semicircle]
∴ \(\angle\)QSR = \(\angle\)PSR - \(\angle\)PSQ = 110° - 90° = 20°.
Similar Questions