Answer: B
Time \((t) = n\) years
Rate of interest \((r) = r\%\)
Interest \((I) = \cfrac{pnr}{25}\) rupees
∴ Principal \((p) = \cfrac{100 \times I}{t \times r}\)
\(= \cfrac{\cfrac{100 \times pnr}{25}}{n \times r} = \cfrac{4pnr}{nr} = 4p\) rupees.
Time \((t) = n\) years
Rate of interest \((r) = r\%\)
Interest \((I) = \cfrac{pnr}{25}\) rupees
∴ Principal \((p) = \cfrac{100 \times I}{t \times r}\)
\(= \cfrac{\cfrac{100 \times pnr}{25}}{n \times r} = \cfrac{4pnr}{nr} = 4p\) rupees.