Q.At an annual simple interest rate of \(r\%\), if the total interest on a principal for \(n\) years is \(\cfrac{pnr}{25}\) rupees, then the amount of the principal is – (a) \(2p\) rupees (b) \(4p\) rupees (c) \(\cfrac{p}{2}\) rupees (d) \(\cfrac{p}{4}\) rupees
Answer: B
Time \((t) = n\) years
Rate of interest \((r) = r\%\)
Interest \((I) = \cfrac{pnr}{25}\) rupees
∴ Principal \((p) = \cfrac{100 \times I}{t \times r}\)
\(= \cfrac{\cfrac{100 \times pnr}{25}}{n \times r} = \cfrac{4pnr}{nr} = 4p\) rupees.
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