In \(\triangle\)ABC, if AB \(= (2p-1)\) cm, AC \(= 2\sqrt2p\) cm, and BC \(= (2p+1)\) cm, then the value of \(\angle\)BAC is...? Let me know if you need further assistance!

Q.In \(\triangle\)ABC, if AB \(= (2p-1)\) cm, AC \(= 2\sqrt2p\) cm, and BC \(= (2p+1)\) cm, then the value of \(\angle\)BAC is...? Let me know if you need further assistance!

Here, AB\(^2\) + AC\(^2\) = \((2p-1)^2 + (2\sqrt{2p})^2\) \(= 4p^2 - 4p + 1 + 8p\) \(= 4p^2 + 4p + 1\) \(= (2p+1)^2\) \(= BC\(^2\) \(\therefore \triangle\)ABC is a right-angled triangle, where BC is the hypotenuse. \(\therefore \angle\)BAC = 90\(^o\)