The statement is true. If the radius \(r\) becomes \(2r\), then the volume changes from \(\frac{4}{3}\pi r^3\) cubic units to \(\frac{4}{3}\pi (2r)^3\) cubic units. ∴ New volume = \(\frac{4}{3}\pi (2r)^3\) cubic units = \(\frac{4}{3}\pi r^3 \times 8\) = 8 × original volume.