Answer: D
Assume the dimensions of the right rectangular prism are \(6a, 5a, 4a\). Therefore, \[ 2(6a \cdot 5a + 5a \cdot 4a + 4a \cdot 6a) = 3700 \] Or, \[ 2(30a^2 + 20a^2 + 24a^2) = 3700 \] Or, \[ 148a^2 = 3700 \] So, \[ a^2 = 25 \] Thus, \[ a = 5 \] Therefore, the volume is: \[ 6a \cdot 5a \cdot 4a = 120a^3 \text{ cubic cm} \] \[ = 120 \times 5^3 \text{ cubic cm} \] \[ = 120 \times 125 \text{ cubic cm} \] \[ = 15000 \text{ cubic cm} \]
Assume the dimensions of the right rectangular prism are \(6a, 5a, 4a\). Therefore, \[ 2(6a \cdot 5a + 5a \cdot 4a + 4a \cdot 6a) = 3700 \] Or, \[ 2(30a^2 + 20a^2 + 24a^2) = 3700 \] Or, \[ 148a^2 = 3700 \] So, \[ a^2 = 25 \] Thus, \[ a = 5 \] Therefore, the volume is: \[ 6a \cdot 5a \cdot 4a = 120a^3 \text{ cubic cm} \] \[ = 120 \times 5^3 \text{ cubic cm} \] \[ = 120 \times 125 \text{ cubic cm} \] \[ = 15000 \text{ cubic cm} \]