Answer: A
\( x^2 + x - 6 = 0 \) Or, \( x^2 + 3x - 2x - 6 = 0 \) Or, \( x(x + 3) - 2(x + 3) = 0 \) Or, \( (x + 3)(x - 2) = 0 \) Therefore, \( x = -3, x = 2 \)
\( x^2 + x - 6 = 0 \) Or, \( x^2 + 3x - 2x - 6 = 0 \) Or, \( x(x + 3) - 2(x + 3) = 0 \) Or, \( (x + 3)(x - 2) = 0 \) Therefore, \( x = -3, x = 2 \)
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